x^2=0.5x+0.06=0

Solution for x^2=0.5x+0.06=0 equation:

x^2=0.5x+0.06=0

We move all terms to the left:

x^2-(0.5x+0.06)=0

We get rid of parentheses

x^2-0.5x-0.06=0

a = 1; b = -0.5; c = -0.06;
Δ = b2-4ac
Δ = -0.52-4·1·(-0.06)
Δ = 0.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{0.49}}{2*1}=\frac{0.5-\sqrt{0.49}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{0.49}}{2*1}=\frac{0.5+\sqrt{0.49}}{2}
$